Accueil
Au hasard
Se connecter
Configuration
Faire un don
À propos de Wikisource
Avertissements
Rechercher
Page
:
Laplace - Œuvres complètes, Gauthier-Villars, 1878, tome 3.djvu/273
Langue
Suivre
Modifier
Le texte de cette page a été
corrigé
et est conforme au fac-similé.
B
2
(
4
)
=
0,006
56716
−
0,007
08386.
B
1
(
0
)
,
B
2
(
5
)
=
0,000
0147361
−
0,006
81821.
A
1
(
1
)
,
B
2
(
6
)
=
−
0,018
3098
−
0,017
0013.
(
A
1
(
1
)
−
B
1
(
0
)
)
,
B
1
(
7
)
=
0,080
9777
+
0
,
0
−
249192.
B
1
(
0
)
−
0,047
8194.
B
1
(
10
)
,
B
1
(
8
)
=
−
0,086
8568
+
0,187
099.
B
1
(
0
)
+
0,055
6224.
B
1
(
9
)
,
B
1
(
9
)
=
−
0,026
3090
−
0,078
7687.
B
1
(
0
)
+
0,050
6541.
B
1
(
8
)
,
B
1
(
10
)
=
0,071
2575
−
0,030
47765.
B
1
(
0
)
+
0,021
1192.
B
1
(
7
)
,
B
0
(
11
)
=
0,421
270
+
0,842
540.
A
1
(
1
)
−
0,337
016.
A
1
(
11
)
+
0,586
564.
B
1
(
0
)
+
0,157
666.
B
1
(
12
)
,
B
1
(
12
)
=
0,000
194141
−
0,168
403.
A
1
(
1
)
+
0,067
3614.
(
A
1
(
11
)
+
1
2
B
1
(
11
)
)
,
B
1
(
13
)
=
0,084
7889
+
0,147
896.
(
A
1
(
1
)
−
1
2
B
1
(
0
)
)
−
0,059
1586.
A
1
(
11
)
,
B
2
(
14
)
=
−
0,012
5619
,
B
2
(
15
)
=
0,003
86625.
{\displaystyle {\begin{aligned}{\rm {B_{2}^{(4)}\ =}}&\quad \,0{,}00656716-0{,}00708386.{\rm {B}}_{1}^{(0)},\\{\rm {B_{2}^{(5)}\ =}}&\quad \,0{,}0000147361-0{,}00681821.{\rm {A}}_{1}^{(1)},\\{\rm {B_{2}^{(6)}\ =}}&-0{,}0183098-0{,}0170013.({\rm {A_{1}^{(1)}-B_{1}^{(0)}),}}\\{\rm {B_{1}^{(7)}\ =}}&\quad \,0{,}0809777+0{,}0-249192.{\rm {B}}_{1}^{(0)}-0{,}0478194.{\rm {B}}_{1}^{(10)},\\{\rm {B_{1}^{(8)}\ =}}&-0{,}0868568+0{,}187099.{\rm {B}}_{1}^{(0)}+0{,}0556224.{\rm {B}}_{1}^{(9)},\\{\rm {B_{1}^{(9)}\ =}}&-0{,}0263090-0{,}0787687.{\rm {B}}_{1}^{(0)}+0{,}0506541.{\rm {B}}_{1}^{(8)},\\{\rm {B_{1}^{(10)}=}}&\quad \,0{,}0712575-0{,}03047765.{\rm {B}}_{1}^{(0)}+0{,}0211192.{\rm {B}}_{1}^{(7)},\\{\rm {B_{0}^{(11)}=}}&\quad \,0{,}421270+0{,}842540.{\rm {A}}_{1}^{(1)}-0{,}337016.{\rm {A}}_{1}^{(11)}+0{,}586564.{\rm {B}}_{1}^{(0)}\\&+0{,}157666.{\rm {B}}_{1}^{(12)},\\{\rm {B_{1}^{(12)}=}}&0{,}000194141-0{,}168403.{\rm {A}}_{1}^{(1)}+0{,}0673614.\left({\rm {A_{1}^{(11)}+{\frac {1}{2}}B_{1}^{(11)}}}\right),\\{\rm {B_{1}^{(13)}=}}&\quad \,0{,}0847889+0{,}147896.{\rm {\left(A_{1}^{(1)}-{\frac {1}{2}}B_{1}^{(0)}\right)-0{,}0591586.A_{1}^{(11)},}}\\{\rm {B_{2}^{(14)}=}}&-0{,}0125619,\\{\rm {B_{2}^{(15)}=}}&\quad \,0{,}00386625.\end{aligned}}}
J’ai conclu de ces équations les valeurs suivantes :
A
2
(
0
)
=
0,007
09262
,
A
1
(
1
)
=
0,202
619
,
A
2
(
2
)
=
−
0,003
72953
,
A
2
(
3
)
=
−
0,003
00427
,
A
2
(
4
)
=
0,028
4957
,
A
1
(
6
)
=
−
0,069
8493
,
A
1
(
7
)
=
0,516
751
,
A
1
(
8
)
=
−
0,207
510
,
A
1
(
9
)
=
0,274
122
,
A
2
(
10
)
=
0,000
81065
,
A
1
(
11
)
=
0,349
068
,
A
2
(
12
)
=
0,002
65066
,
A
1
(
13
)
=
0,007
5875
,
A
2
(
14
)
=
−
0,012
9890
,
{\displaystyle {\begin{aligned}{\rm {A_{2}^{(0)}\ =}}&\quad \,0{,}00709262,\\{\rm {A_{1}^{(1)}\ =}}&\quad \,0{,}202619,\\{\rm {A_{2}^{(2)}\ =}}&-0{,}00372953,\\{\rm {A_{2}^{(3)}\ =}}&-0{,}00300427,\\{\rm {A_{2}^{(4)}\ =}}&\quad \,0{,}0284957,\\{\rm {A_{1}^{(6)}\ =}}&-0{,}0698493,\\{\rm {A_{1}^{(7)}\ =}}&\quad \,0{,}516751,\\{\rm {A_{1}^{(8)}\ =}}&-0{,}207510,\\{\rm {A_{1}^{(9)}\ =}}&\quad \,0{,}274122,\\{\rm {A_{2}^{(10)}=}}&\quad \,0{,}00081065,\\{\rm {A_{1}^{(11)}=}}&\quad \,0{,}349068,\\{\rm {A_{2}^{(12)}=}}&\quad \,0{,}00265066,\\{\rm {A_{1}^{(13)}=}}&\quad \,0{,}0075875,\\{\rm {A_{2}^{(14)}=}}&-0{,}0129890,\end{aligned}}}