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Laplace - Œuvres complètes, Gauthier-Villars, 1878, tome 3.djvu/256
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0
=
(
1
−
m
2
)
A
2
(
5
)
+
3
m
2
2
a
a
ı
{\displaystyle 0=\left(1-m^{2}\right){\rm {A}}_{2}^{(5)}+{\frac {3m^{2}}{2}}{\frac {a}{a_{\text{ı}}}}}
×
{
1
+
e
2
+
γ
2
4
+
9
8
e
′
2
+
(
B
1
(
7
)
+
B
1
(
8
)
)
γ
2
m
2
−
3
2
(
1
+
2
m
)
A
2
(
0
)
−
2
(
1
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m
)
(
3
−
2
m
)
(
3
−
m
)
(
2
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m
)
(
2
−
m
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A
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0
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−
2
A
2
(
5
)
−
(
2
−
3
m
)
A
2
(
4
)
+
(
B
1
(
9
)
+
B
1
(
10
)
)
B
1
(
0
)
γ
2
m
2
−
A
2
(
5
)
−
11
C
2
(
6
)
−
2
C
2
(
9
)
+
2
C
2
(
10
)
}
{\displaystyle \times \left\{{\begin{aligned}1&+e^{2}+{\frac {\gamma ^{2}}{4}}+{\frac {9}{8}}e'^{2}+\left({\rm {B}}_{1}^{(7)}+{\rm {B}}_{1}^{(8)}\right){\frac {\gamma ^{2}}{m^{2}}}-{\frac {3}{2}}(1+2m){\rm {A}}_{2}^{(0)}\\\\&-{\frac {2(1-2m)(3-2m)(3-m)}{(2-3m)(2-m)}}{\rm {A}}_{2}^{(0)}-2{\rm {A}}_{2}^{(5)}-(2-3m){\rm {A}}_{2}^{(4)}\\\\&+{\rm {\left(B_{1}^{(9)}+B_{1}^{(10)}\right)B_{1}^{(0)}}}{\frac {\gamma ^{2}}{m^{2}}}-{\rm {A_{2}^{(5)}-11C_{2}^{(6)}-2C_{2}^{(9)}+2C_{2}^{(10)}}}\end{aligned}}\right\}}
+
6
m
[
4
A
2
(
0
)
+
A
2
(
3
)
−
A
2
(
4
)
−
10
A
1
(
1
)
e
2
+
5
2
(
A
1
(
7
)
−
A
1
(
6
)
)
e
2
]
,
{\displaystyle +6m\left[4{\rm {A_{2}^{(0)}+A_{2}^{(3)}-A_{2}^{(4)}-10A_{1}^{(1)}}}e^{2}+{\frac {5}{2}}\left({\rm {A_{1}^{(7)}-A_{1}^{(6)}}}\right)e^{2}\right],}
0
=
[
1
−
(
2
−
m
−
c
)
2
]
A
1
(
6
)
+
3
2
m
2
a
a
ı
{\displaystyle 0=\left[1-(2-m-c)^{2}\right]{\rm {A}}_{1}^{(6)}+{\frac {3}{2}}m^{2}{\frac {a}{a_{\text{ı}}}}}
×
{
3
+
2
m
−
c
4
+
2
+
m
2
−
m
−
c
−
3
2
A
1
(
1
)
−
A
1
(
6
)
−
(
3
+
m
+
c
2
+
4
2
−
m
−
c
)
A
1
(
9
)
}
{\displaystyle \times \left\{{\begin{aligned}{\frac {3+2m-c}{4}}+{\frac {2+m}{2-m-c}}-{\frac {3}{2}}{\rm {A}}_{1}^{(1)}-{\rm {A}}_{1}^{(6)}\\\\-\left({\frac {3+m+c}{2}}+{\frac {4}{2-m-c}}\right){\rm {A}}_{1}^{(9)}\end{aligned}}\right\}}
0
=
[
1
−
(
2
−
3
m
−
c
)
2
]
A
1
(
7
)
−
3
2
m
2
a
a
ı
{\displaystyle 0=\left[1-(2-3m-c)^{2}\right]{\rm {A}}_{1}^{(7)}-{\frac {3}{2}}m^{2}{\frac {a}{a_{\text{ı}}}}}
×
{
7
(
3
+
6
m
−
c
4
+
7
(
2
+
3
m
)
2
−
3
m
−
c
+
3
2
A
1
(
1
)
+
A
1
(
7
)
+
(
3
−
m
−
c
2
+
4
2
−
3
m
−
c
)
A
1
(
8
)
}
{\displaystyle \times \left\{{\begin{aligned}{\frac {7(3+6m-c}{4}}+{\frac {7(2+3m)}{2-3m-c}}+{\frac {3}{2}}{\rm {A}}_{1}^{(1)}\\\\+{\rm {A}}_{1}^{(7)}+\left({\frac {3-m-c}{2}}+{\frac {4}{2-3m-c}}\right){\rm {A}}_{1}^{(8)}\end{aligned}}\right\}}
0
=
[
1
−
(
c
+
m
)
2
]
A
1
(
8
)
−
3
2
m
2
a
a
ı
{\displaystyle 0=\left[1-(c+m)^{2}\right]{\rm {A}}_{1}^{(8)}-{\frac {3}{2}}m^{2}{\frac {a}{a_{\text{ı}}}}}
×
{
3
+
2
m
2
−
(
1
+
2
m
+
c
4
+
2
c
+
m
)
A
1
(
1
)
+
A
1
(
8
)
+
(
1
+
3
m
+
c
2
+
4
c
+
m
)
A
1
(
7
)
}
{\displaystyle \times \left\{{\begin{aligned}{\frac {3+2m}{2}}-\left({\frac {1+2m+c}{4}}+{\frac {2}{c+m}}\right){\rm {A}}_{1}^{(1)}\\\\+{\rm {A}}_{1}^{(8)}+\left({\frac {1+3m+c}{2}}+{\frac {4}{c+m}}\right){\rm {A}}_{1}^{(7)}\end{aligned}}\right\}}
0
=
[
1
−
(
c
−
m
)
2
]
A
1
(
9
)
−
3
2
m
2
a
a
ı
{\displaystyle 0=\left[1-(c-m)^{2}\right]{\rm {A}}_{1}^{(9)}-{\frac {3}{2}}m^{2}{\frac {a}{a_{\text{ı}}}}}
×
{
3
−
2
m
2
+
A
1
(
9
)
+
7
(
1
+
2
m
+
c
4
+
2
c
−
m
)
A
1
(
1
)
+
(
1
+
m
+
c
2
+
4
c
−
m
)
A
1
(
6
)
}
{\displaystyle \times \left\{{\begin{aligned}{\frac {3-2m}{2}}+{\rm {A}}_{1}^{(9)}+7\left({\frac {1+2m+c}{4}}+{\frac {2}{c-m}}\right){\rm {A}}_{1}^{(1)}\\\\+\left({\frac {1+m+c}{2}}+{\frac {4}{c-m}}\right){\rm {A}}_{1}^{(6)}\end{aligned}}\right\}}
0
=
(
1
−
4
c
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)
A
2
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10
)
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m
2
a
a
ı
(
1
−
B
0
(
11
)
γ
2
m
2
−
A
2
(
10
)
)
,
{\displaystyle 0=\left(1-4c^{2}\right){\rm {A}}_{2}^{(10)}+{\frac {3}{2}}m^{2}{\frac {a}{a_{\text{ı}}}}\left(1-{\rm {B}}_{0}^{(11)}{\frac {\gamma ^{2}}{m^{2}}}-{\rm {A}}_{2}^{(10)}\right),}
0
=
[
1
−
(
2
c
−
2
+
2
m
)
2
]
A
1
(
11
)
+
3
4
m
2
a
a
ı
{\displaystyle 0=\left[1-(2c-2+2m)^{2}\right]{\rm {A}}_{1}^{(11)}+{\frac {3}{4}}m^{2}{\frac {a}{a_{\text{ı}}}}}
×
{
2
+
11
m
+
8
m
2
2
−
10
+
19
m
+
8
m
2
2
c
−
2
+
2
m
+
4
A
1
(
1
)
+
8
A
1
(
10
)
+
10
(
A
1
(
1
)
)
2
2
c
−
2
+
2
m
−
2
A
1
(
11
)
}
{\displaystyle \times \left\{{\begin{aligned}{\frac {2+11m+8m^{2}}{2}}-{\frac {10+19m+8m^{2}}{2c-2+2m}}\\\\+4{\rm {A}}_{1}^{(1)}+{\frac {8{\rm {A}}_{1}^{(10)}+10({\rm {A}}_{1}^{(1)})^{2}}{2c-2+2m}}-2{\rm {A}}_{1}^{(11)}\end{aligned}}\right\}}
0
=
(
1
−
4
g
2
)
A
2
(
12
)
+
a
a
ı
(
g
2
−
1
−
3
4
a
−
a
ı
a
+
3
8
m
2
−
3
2
m
2
A
2
(
12
)
)
,
{\displaystyle 0=\left(1-4g^{2}\right){\rm {A}}_{2}^{(12)}+{\frac {a}{a_{\text{ı}}}}\left(g^{2}-1-{\frac {3}{4}}{\frac {a-a_{\text{ı}}}{a}}+{\frac {3}{8}}m^{2}-{\frac {3}{2}}m^{2}{\rm {A}}_{2}^{(12)}\right),}
0
=
[
1
−
(
2
g
−
2
+
2
m
)
2
]
A
1
(
13
)
+
3
4
m
2
a
a
ı
{\displaystyle 0=\left[1-(2g-2+2m)^{2}\right]{\rm {A}}_{1}^{(13)}+{\frac {3}{4}}m^{2}{\frac {a}{a_{\text{ı}}}}}
×
{
3
+
2
m
−
2
g
4
+
4
g
2
−
1
4
(
1
−
m
)
−
2
+
m
2
g
−
2
+
2
m
+
2
B
1
(
0
)
m
2
−
2
A
1
(
13
)
+
8
A
2
(
12
)
2
g
−
2
+
2
m
}
{\displaystyle \times \left\{{\begin{aligned}{\frac {3+2m-2g}{4}}+{\frac {4g^{2}-1}{4(1-m)}}-{\frac {2+m}{2g-2+2m}}\\\\+{\frac {2{\rm {B}}_{1}^{(0)}}{m^{2}}}-2{\rm {A}}_{1}^{(13)}+{\frac {8{\rm {A}}_{2}^{(12)}}{2g-2+2m}}\end{aligned}}\right\}}
0
=
(
1
−
4
m
2
)
A
2
(
14
)
+
3
2
m
2
a
a
ı
(
3
2
−
A
2
(
14
)
)
.
{\displaystyle 0=\left(1-4m^{2}\right){\rm {A}}_{2}^{(14)}+{\frac {3}{2}}m^{2}{\frac {a}{a_{\text{ı}}}}\left({\frac {3}{2}}-{\rm {A}}_{2}^{(14)}\right).}