no 2 de la Section deuxième ; il suffira pour les appliquer au cas présent d’ychanger r {\displaystyle r} en r ″ {\displaystyle r''} et r ′ {\displaystyle r'} en r ‴ . {\displaystyle r'''.}
Faisant donc z = r ‴ r ″ = 0,656 301 , {\displaystyle z={\frac {r'''}{r''}}=0{,}656301,} on aura
et ensuite
9. Or
et de là on aura pour les inégalités dues à Mars,
en 
et 
en 
on aura
![{\displaystyle {\begin{alignedat}{2}r'''[r'',r''']\ \,=&0{,}751819\qquad \qquad &\log .\quad &9{,}8761134,\\r'''[r'',r''']_{1}=&0{,}527995&&9{,}7226300,\\r'''[r'',r''']_{2}=&0{,}266138&&9{,}4251068,\\r'''[r'',r''']_{3}=&0{,}147346&&9{,}1683370,\\r'''[r'',r''']_{4}=&0{,}085226&&8{,}9305737,\\r'''[r'',r''']_{5}=&0{,}050547&&8{,}7036967,\\r'''[r'',r''']_{6}=&0{,}030443&&8{,}4835038,\\\ldots \ldots \ldots \ldots &\ldots \ldots \ldots &&\ldots \ldots \ldots ,\end{alignedat}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/e9277e7deca5d7606d3a2bbc46ba2709c8fa8235)
![{\displaystyle {\begin{alignedat}{2}2r'''^{2}{\frac {d[r'',r''']}{r'''}}\ \,=&0{,}528991\qquad \qquad &\log .\quad &9{,}7234483,\\2r'''^{2}{\frac {d[r'',r''']_{1}}{r'''}}=&1{,}612040&&0{,}2073758,\\2r'''^{2}{\frac {d[r'',r''']_{2}}{r'''}}=&1{,}379525&&0{,}1397296,\\2r'''^{2}{\frac {d[r'',r''']_{3}}{r'''}}=&1{,}069307&&0{,}0291023,\\2r'''^{2}{\frac {d[r'',r''']_{4}}{r'''}}=&0{,}793601&&9{,}8996022,\\2r'''^{2}{\frac {d[r'',r''']_{5}}{r'''}}=&0{,}574695&&9{,}7594374,\\2r'''^{2}{\frac {d[r'',r''']_{6}}{r'''}}=&0{,}409944&&9{,}6127245,\\\ldots \ldots \ldots \ldots \ldots &\ldots \ldots \ldots &&\ldots \ldots \ldots ,\end{alignedat}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/9bc09f3d17a5b2bd24f6afe20a9434996ca5e218)
![{\displaystyle {\begin{aligned}-\mathrm {T} '&\left[+3{,}881779\sin(p'''-p'')+31{,}170190\sin 2(p'''-p'')\right.\\&\left.\ \ -1{,}925284\sin 3(p'''-p'')-0{,}420867\sin 4(p'''-p''-\ldots \right].\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/af128c5825565d6277270dfda20156244942740a)
