conservant les mêmes valeurs des quantités 
on aura dans le cas présent
![{\displaystyle {\begin{aligned}&r^{2}{\frac {d[r,r']}{dr}}\,\ =z\left[\left(1+z^{2}\right)(0)-z(1)\right],\\&r^{2}{\frac {d[r,r']_{1}}{dr}}=z\left[\ 4\ z(0)-\left(1+z^{2}\right)(1)\right],\\&r^{2}{\frac {d[r,r']_{2}}{dr}}=z\left[{\frac {2}{3}}z(1)-{\frac {1}{3}}\left(1+z^{2}\right)(2)\right],\\&r^{2}{\frac {d[r,r']_{3}}{dr}}=z\left[{\frac {2}{5}}z(2)-{\frac {1}{5}}\left(1+z^{2}\right)(3)\right],\\&\ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots ,\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/7db5acd4000c85bcf4b3638f4245aa42d3eda15e)
![{\displaystyle {\begin{aligned}&2r'^{2}{\frac {d[r,r']}{dr}}\,\ =-r'[r,r']\ \,+z\left(1-z^{2}\right)(0),\\&2r'^{2}{\frac {d[r,r']_{1}}{dr}}=-r'[r,r']_{1}+z\left(1-z^{2}\right)(1),\\&2r'^{2}{\frac {d[r,r']_{2}}{dr}}=-r'[r,r']_{2}+z\left(1-z^{2}\right)(2),\\&\ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots ,\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/9604702b124c3fa16455d0da80d0f8f6c37ccf14)
Mais, comme on a déjà calculé dans la Section précédente les valeurs des quantités
![{\displaystyle r[r,r'],\quad r[r,r']_{1},\quad r[r,r']_{2},\ldots ,}](https://wikimedia.org/api/rest_v1/media/math/render/svg/ebfee0218c805ad3119c04d27ad6277ad9702cd3)
ainsi que celles de
![{\displaystyle 2r^{2}{\frac {d[r,r']}{dr}},\quad 2r^{2}{\frac {d[r,r']_{1}}{dr}},\quad 2r^{2}{\frac {d[r,r']_{2}}{dr}},\ldots ,}](https://wikimedia.org/api/rest_v1/media/math/render/svg/4a33d25313443afd7b03320fe2a9a34599df19b9)
on pourra déduire immédiatement de ces valeurs celles des quantités ci-dessus, en faisant
![{\displaystyle {\begin{aligned}&r'[r,r']\ \,=z\ r[r,r'],\\&r'[r,r']_{1}=z\ r[r,r']_{1},\\&r'[r,r']_{2}=z\ r[r,r']_{2},\\&\ldots \ldots \ldots \ldots \ldots \ldots \,;\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/508ecd41719baddfff25855f3fa4711cd5416c04)
![{\displaystyle {\begin{aligned}&2r'^{2}{\frac {d[r,r']}{dr'}}\,\ =-2r'[r,r']\ \,-z\times 2r^{2}{\frac {d[r,r']}{dr}},\\&2r'^{2}{\frac {d[r,r']_{1}}{dr'}}=-2r'[r,r']_{1}-z\times 2r^{2}{\frac {d[r,r']_{1}}{dr}},\\&2r'^{2}{\frac {d[r,r']_{2}}{dr'}}=-2r'[r,r']_{2}-z\times 2r^{2}{\frac {d[r,r']_{2}}{dr}},\\&\ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots \ldots ,\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/9d84029402beef1d9a531fb0cbc795d5405f3210)
